Lesson 2 of 15
Trace Current Capacity
Trace Current Capacity (IPC-2221)
How much current can a trace carry before overheating? The IPC-2221 standard provides empirical formulas based on temperature rise.
I = K × ΔT^0.44 × A^0.725
Where:
- I = maximum current (Amps)
- K = 0.048 for external traces, 0.024 for internal traces
- ΔT = allowed temperature rise above ambient (°C)
- A = cross-sectional area of the trace (mils²) — 1 mil = 0.0254 mm
The cross-section area in mils²:
A = (width in mils) × (thickness in mils)
Common trace thicknesses in mils: 1 oz = 1.378 mils, 2 oz = 2.756 mils.
Example: External 10 mil wide, 1 oz trace, 10°C rise:
- A = 10 × 1.378 = 13.78 mils²
- I = 0.048 × 10^0.44 × 13.78^0.725 ≈ 0.048 × 2.754 × 6.68 ≈ 0.884 A
Your Task
Implement traceCurrentCapacity(widthMm, thicknessMm, deltaT, external):
widthMm,thicknessMm: dimensions in mmdeltaT: temperature rise in °Cexternal: boolean (true = external trace)- Returns max current in Amps
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